Diketahui:
tbunyi + tbaru = 3,4 s
vbunyi =340 m/s2
Ditanya :
tinggi tebing???
Jawab :
Sbunyi = 1/2.g.tbunyi^ =>> (gerak jatuh bebas)
Sbatu = V.tbunyi
Sbunyi = Sbatu
V.tbunyi = 1/2.g.tbatu^
V. (3,4-tbatu) = 1/2.10.tbatu^
340(3,4-tbatu)= 5tbatu^
1156-340tbatu = 5 tbatu^
5tbatu^ + 340 tbatu-1156 = 0
tbatu = 1> -b-akar b^-4ac : 2a
= -340-akar (340)^-4.5.-1156
= -71,245 (TM)
= 2> -b + akar b^-4ac : 2a
= -340 + akar (340)^-4.5.-1156
= 3,245 sekon
Jadi Sbatu= 1/2 g.t^
= 1/2.10.(3,245)^
=52,65 meter
Oleh: Andriani Patricia Witanto / X-j / 08
Tidak ada komentar:
Posting Komentar